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By Bo N. Nilsson
The textbook contains greater than 100 routines and recommendations to utilized difficulties compatible for classes in simple radiation physics. every one bankruptcy starts off with a precis of vital definitions and family necessary for the topic.
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Example text
26) results in Multiplying with λ2 and dividing with eλ2t gives The production rate of radionuclides is given by where is the neutron fluence rate, σ is the reaction cross section and N0 is the number of target nuclei at t=0. Combining Eq. 40·60) s−1 (decay constant for 104mRh) λ2=In2/42 s−1 (decay constant for 104Rh) t1=60 s (irradiation time) t2=600 s (irradiation time) Data inserted in Eq. 32) gives for t=60 s Data inserted in Eq. 98A2(∞) Answer: The 104Rh activity is 58% of the saturation activity after 60 s and 98% of the saturation activity after 600 s.
The mean energy is expressed as where rp is the electron range. However, this expression holds better for the most probable energy and should not be used when accurate calculations are necessary. In dosimetry today most data of electron energies and thus stopping power values are based on Monte Carlo calculations and these data should be used if possible. 1. What is the maximal δ-particle energy that can be obtained for a proton, an electron and positron respectively, if their kinetic energy is 10 MeV?
Thus and Mass energy absorption coefficient The mass energy absorption coefficient is the product of the mass energy transfer coefficient μtr /ρ and (1-g) where g is the fraction of energy liberated by charged particles which is lost in radiative processes as bremsstrahlung and annihilation in flight. μen /ρ is an important coefficient when calculating the absorbed dose as it gives the energy absorbed in collisions of charged particles with electrons, and thus to ionization in the medium. For low photon energies and low atomic numbers the numerical difference between μen /ρ and μtr /ρ is small as the contribution to bremsstrahlung is small.