Field Theory by S. Roman

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Is a double root of  ²%³. 7 Testing for Irreducibility We next discuss some methods for testing a polynomial for irreducibility. Note first that ²%³  - ´%µ is irreducible if and only if ²% b ³ is irreducible, for   - . This is often a useful device in identifying irreducibility. 36 Field Theory Localization Sometimes it is possible to identify irreducibility by changing the base ring. In particular, suppose that 9 and : are rings and ¢ 9 ¦ : is a ring homomorphism. If a polynomial ²%³  9´%µ is degreewise reducible, then ²%³ ~  ²%³²%³ where deg² ³  deg²³ and deg²³  deg²³.

Is the order of . 2 implies that . … Polynomials as Functions In the customary way, a polynomial ²%³  9´%µ can be thought of as a function on 9. Of course, the zero polynomial is also the zero function. However, the converse is not true! For example, the nonzero polynomial ²%³ ~ % c % in { ´%µ is the zero function on { . This raises the question of how to decide, based on the zero set of a polynomial, when that polynomial must be the zero polynomial. 3 ensures that if ²%³ has degree at most  but has more than  zeros, then it must be the zero polynomial.

Finally, if ¸, ¹ is a family of fields, each algebraic over - , then so is , , since an element of , is also an element of a composite of only a finite number of members of the family. … The algebraic closure of the rational numbers r in the complex numbers d is called the field 7 of algebraic numbers. We saw in the previous chapter that there is an irreducible polynomial  ²%³  {´%µ of every positive degree . 1 does not hold: algebraic extensions need not be finite. Note that if   s is an algebraic number, it also satisfies a polynomial over the integers.

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