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By John Baez
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5. If C = Cat, elt(D) = {functors f : 1 → D, where 1 is the terminal category in Cat}. functors f : 1 → D are in 1 − 1 correspondence with the objects of D. 1. Suppose C is a category with terminal object 1 ∈ C. Then there’s a functor elt : C → Set with elt( X ) = Hom(1, X ), ∀ X ∈ C and given any morphism g : X → YinC, elt( g) : elt( X ) → elt(Y ) is defined as follows: 1 f X g elt( g) f = g◦ f Y 43 g Proof: elt preserve composition: given X Y h Z we need elt(h ◦ g) = elt(h) ◦ elt( g) f 1 X g Y h Z Given f ∈ elt( X ) we have elt(h ◦ g) f = = = = (h ◦ g) ◦ f h ◦ (g ◦ f ) h ◦ (elt( g) f ) elt(h)(elt( g)( f )) Similarly elt(1x ) f = 1x ◦ f = f , for all f ∈ elt( X ).
Elements of a set X are in 1 − 1 correspondence with functions f : 1 → X, where 1 is a terminal object in Set (1 = a one element set). 1. If C is a category with a terminal object, an element of an object X ∈ C is a morphism 1 → X. We define the set elt(X) to be Hom(1, X ). 3. e. the terminal object in Top}. In fact, elt(X) is in 1 − 1 correspondence with the underlying set of X: Given x ∈ X, f : {∗} → X where ∗ → x, and conversely any such f (∗) ∈ X. 4. e. the terminal object in Grp}. So elt(G) has just one element: there’s just one homomorphism f : 1 → G, since 1 is also initial!
Then check it’s really a functor: For example, check it preserves composition. h X Y g f X g◦ h◦ f = Hom( ϕ)(h) Y Given functors F : C → D and U : D → C, how can we say that the isomorphism HomD ( F ( X ), Y ) ∼ = HomC ( X, U (Y )) is natural? 2 Hom α s 1C ×U Set Hom Cop × C Examples of Adjunctions Let’s at first downplay the naturality condition and look at examples focusing on bijections. 3. The forgetful functor U : Grp → Set sends each group G to its underlying set U ( G ). The free functor F : Set → Grp sends each set S to the free group on it F (S).