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By Bernard Morrill
Answer guide for an creation to Equilibrium Thermodynamics
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Extra info for Solution Manual for an Introduction to Equilibrium Thermodynamics
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565 51 9-5 cont. 9-6 cont. 0 ds = (R/V) dV valid for a constant temperature process', in general, dS =R [Vl But actual temperature is 560 AT = (560 - 543) = 17°F Q = mc^fcT continued dV_ + As t0t % =R i l n ^ continued [5 dV- \ J + \ V 2 J 52 9-7 cont. No.
2 . 5 4 500 1-h_ = v. I ^0,5069 continued 2 1 47 8-18 cont. h -h 2 8-19 cont. 507 . 3£ = 38. RR 8-19 T A slight increase 8-20 work =w - w net «j> p (h T = 700 F 3 T = 700°F. 5069 psia Q. 6,j Wj, 48 9-19 cont. 04814 2 Now h =h +Ulh = c (t -32) +u>hr. 4 2 h = 70,830 c 2 2 a 2 p w K 0 "i t=no° m - m (vJ. - U)) Then mu a 2 1 h = = 4 8 . J2 l. continued w 2 f w 2 . h i . 0564 v 2 g . 1997 l 1 l At 105°F ) :^n " f 2 (h 49 Chapter 9 9-1 cont. 71 poia 50 9-4 cont. 248 CO. 248 V H. 177 M = 3 1 . 180 BTU/lbm °R 9-4 Volumetric analysis x.
1 . 412 = -700 + 2 ^ T = ? 2 This is not a violation of the 2nd law. 0 V ^ H = ^ « Q 1 2 1 2 2 pV P dU = 0 Then T = 560 P = 30 2 T = 20 P l ^ 1 m (1) the atmosphere (2) the chemical x 5 6 Q ? 4821 BTU/lbm-°R s Indeterminate 5-10 5-8 W= Equilibrium temp. 850 „ Q. 1$ c 175 The efficiency of the turbine is greater than the Carnot cycle operating between the given temperature limits. This is not possible. ) c) = P=T g = F + TS = U = U (S V N ) f f ± L[fi] = g b) L[J] = (1 - V ^ r ) F -P continued = F + pV = G N.